Tg(п/4+a/2)-tg(п/4-a/2)

Лебедев Дмитрий Сергеевич

Учитель математики

Проверено учителем

Для упрощения выражения tg(π4+α2)tg(π4α2)tg open paren the fraction with numerator pi and denominator 4 end-fraction plus the fraction with numerator alpha and denominator 2 end-fraction close paren minus tg open paren the fraction with numerator pi and denominator 4 end-fraction minus the fraction with numerator alpha and denominator 2 end-fraction close paren воспользуемся формулами тангенса суммы и разности аргументов, а также табличным значением tg(π4)=1tg open paren the fraction with numerator pi and denominator 4 end-fraction close paren equals 1 . 1. Применение формул сложения Формула тангенса суммы: tg(x+y)=tg x+tg y1tg xtg ytg open paren x plus y close paren equals the fraction with numerator tg x plus tg y and denominator 1 minus tg x center dot tg y end-fraction . Для первого слагаемого ( x=π4,y=α2x equals the fraction with numerator pi and denominator 4 end-fraction comma y equals the fraction with numerator alpha and denominator 2 end-fraction ): tg(π4+α2)=1+tgα21tgα2tg open paren the fraction with numerator pi and denominator 4 end-fraction plus the fraction with numerator alpha and denominator 2 end-fraction close paren equals the fraction with numerator 1 plus tg the fraction with numerator alpha and denominator 2 end-fraction and denominator 1 minus tg the fraction with numerator alpha and denominator 2 end-fraction end-fraction Для второго слагаемого ( x=π4,y=α2x equals the fraction with numerator pi and denominator 4 end-fraction comma y equals the fraction with numerator alpha and denominator 2 end-fraction ): tg(π4α2)=1tgα21+tgα2tg open paren the fraction with numerator pi and denominator 4 end-fraction minus the fraction with numerator alpha and denominator 2 end-fraction close paren equals the fraction with numerator 1 minus tg the fraction with numerator alpha and denominator 2 end-fraction and denominator 1 plus tg the fraction with numerator alpha and denominator 2 end-fraction end-fraction 2. Вычитание дробей Составим разность и приведем к общему знаменателю (1tgα2)(1+tgα2)open paren 1 minus tg the fraction with numerator alpha and denominator 2 end-fraction close paren open paren 1 plus tg the fraction with numerator alpha and denominator 2 end-fraction close paren : 1+tgα21tgα21tgα21+tgα2=(1+tgα2)2(1tgα2)21tg2α2the fraction with numerator 1 plus tg the fraction with numerator alpha and denominator 2 end-fraction and denominator 1 minus tg the fraction with numerator alpha and denominator 2 end-fraction end-fraction minus the fraction with numerator 1 minus tg the fraction with numerator alpha and denominator 2 end-fraction and denominator 1 plus tg the fraction with numerator alpha and denominator 2 end-fraction end-fraction equals the fraction with numerator open paren 1 plus tg the fraction with numerator alpha and denominator 2 end-fraction close paren squared minus open paren 1 minus tg the fraction with numerator alpha and denominator 2 end-fraction close paren squared and denominator 1 minus tg squared the fraction with numerator alpha and denominator 2 end-fraction end-fraction 3. Раскрытие скобок и упрощение Раскроем квадраты в числителе: (1+2tgα2+tg2α2)(12tgα2+tg2α2)=4tgα2open paren 1 plus 2 tg the fraction with numerator alpha and denominator 2 end-fraction plus tg squared the fraction with numerator alpha and denominator 2 end-fraction close paren minus open paren 1 minus 2 tg the fraction with numerator alpha and denominator 2 end-fraction plus tg squared the fraction with numerator alpha and denominator 2 end-fraction close paren equals 4 tg the fraction with numerator alpha and denominator 2 end-fraction Получаем промежуточное выражение: 4tgα21tg2α2the fraction with numerator 4 tg the fraction with numerator alpha and denominator 2 end-fraction and denominator 1 minus tg squared the fraction with numerator alpha and denominator 2 end-fraction end-fraction 4. Использование формулы двойного угла Вспомним формулу тангенса двойного угла: tg(2x)=2tg x1tg2xtg open paren 2 x close paren equals the fraction with numerator 2 tg x and denominator 1 minus tg squared x end-fraction . Преобразуем наше выражение так, чтобы выделить эту формулу: 4tgα21tg2α2=2(2tgα21tg2α2)=2tg(2α2)=2tg αthe fraction with numerator 4 tg the fraction with numerator alpha and denominator 2 end-fraction and denominator 1 minus tg squared the fraction with numerator alpha and denominator 2 end-fraction end-fraction equals 2 center dot open paren the fraction with numerator 2 tg the fraction with numerator alpha and denominator 2 end-fraction and denominator 1 minus tg squared the fraction with numerator alpha and denominator 2 end-fraction end-fraction close paren equals 2 center dot tg open paren 2 center dot the fraction with numerator alpha and denominator 2 end-fraction close paren equals 2 tg alpha Ответ: 2tg α2 tg alpha Хотите ли вы разобрать другой способ решения через формулу разности тангенсов tg xtg y=sin(xy)cosxcosytg x minus tg y equals the fraction with numerator sine open paren x minus y close paren and denominator cosine x cosine y end-fraction ?

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